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How to Remove Duplicate Values From Java ArrayList

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Editorial,  3 min read,  2.59K views, updated on Sept. 17, 2023

This example shows how to remove duplicate from ArrayList. The easiest way to remove duplicate is by passing the List to an Set. As set doesn’t support duplicates it will omit the duplicate values. Once you have the Set you can again pass it back to ArrayList.

Duplicate Values From Java ArrayList using HashSet

import java.util.ArrayList;
import java.util.HashSet;
import java.util.Iterator;
import java.util.List;

public class RemoveDuplicate {
	public static void main(String[] args) {
		List sourceList = new ArrayList();

		sourceList.add("object1");
		sourceList.add("object2");
		sourceList.add("object2");
		sourceList.add("object3");
		sourceList.add("object4");
		sourceList.add("object2");

		List newList = new ArrayList(new HashSet(
				sourceList));
		Iterator it = newList.iterator();
		while (it.hasNext()) {
			System.out.println(it.next());
		}

	}
}

Output

object3
object4
object1
object2

In this above example we have removed duplicates from the ArrayList but we will loose the sequencing index. If you want to preserve the order of data use LinkedHashSet rather HashSet. Find an example below

Duplicate Values From Java ArrayList using LinkedHashSet

import java.util.ArrayList;
import java.util.Iterator;
import java.util.LinkedHashSet;
import java.util.List;

public class RemoveDuplicate {
	public static void main(String[] args) {
		List sourceList = new ArrayList();

		sourceList.add("object1");
		sourceList.add("object2");
		sourceList.add("object2");
		sourceList.add("object3");
		sourceList.add("object4");
		sourceList.add("object2");

		List newList = new ArrayList(new LinkedHashSet(
				sourceList));
		Iterator it = newList.iterator();
		while (it.hasNext()) {
			System.out.println(it.next());
		}

	}
}

Output

object1
object2
object3
object4

Java Collection APIs

The Collections framework in Java defines numerous different data structures in which you can store, group, and retrieve objects.

>> CHECK OUT THE COURSE

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